stuck and cant figure it out

Question

can i get help in solving this. 

 

the question is:

 

solve by using quadramatic formula:

 

3p2 + 7p + 4 = 0

 

how do i figure this out by using a calculator.

 

 

Answer 1

Hi Ruby,

 

Let's begin by writing the standard form of the quadratic equation:

    ax² + bx + c = 0

 

Next, let's write the quadratic formula:

    x = [-b +/- √(b² - 4ac)] / 2a

 

Now, let's see what are our coefficients (a, b, c) are in our given equation using the standard form of the quadratic equation:

    ax² + bx + c = 0   [standard form] 

    3p² + 7p + 4 = 0  [our variable is p instead of x] 

    a=3; b=7; c=4

 

Let's plug in our values for a, b, c into the quadratic formula and solve for p:

    p = [-b +/- √(b² - 4ac)] / 2a

    p = [-7 +/- √(7² - 4(3)(4)] / 2(3)

    p = [-7 +/- √(49 - 48)] / 6

    p = [-7 +/- √1] / 6

    p = [-7 +/- 1] / 6

    p = (-7 + 1)/6 = -(6/6) = -1

    p = (-7 - 1)/6 = -(8/6) = -(4/3)

 

Thanks for submitting this problem and glad to help.

 

God bless, Jordan. 

Answer 2

3p²+7p+4=0

[-b±√(b²-4ac)]/2a

[-7±√(49-48)]/6

[-7±√1]/6

(-7±1)/6

(-7+1)/6=-6/6=-1

(-7-1)/6=-8/6=-4/3

it's easier to factor...

(3p+4)(p+1)=0

3p+4=0

3p=-4

p=-4/3

p+1=0

p=-1

Answer 3

The quadratic formula for this equation is

 

p = (-b ± √(b² - 4ac)) / 2a

 

 

The equation is

 

ap² + bp + c = 0

 

 

where:

a = 3

b = 7

c = 4

 

Plug in these vales into the formula to solve for p.   You will two solutions because of the plus/minus sign.