**a) T=10o C,V=9m/sec**

**b)T=0o C,V=15m/sec**

**c)T=10o C,V =20 m/sec**

**d) The formula to find the wind chill temperature is given by:**

**10.45+ 10V-square root sign-V)x(33-T)**

**W=33 and this is over 22**

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Torrance, CA

The windchill index equation contains V and T. So for a, b, and c, you just plug in the V and T values and solve the equation.

I'm not sure what d) is asking for, but if W=33 and it's over 22, then (33-T) = 22, which means T = 11. If you use the equation and substitute 33 for W and 11 for T, you should be able to solve for V.

You will get:

v - 10(sqrt(v) - 8.95=0 While this doesn't seem easy to solve, it is if you let x=sqrt(v). Then you end up with a quadratic equation: x^{ 2
}- 10x - 8.95 = 0 and you can use the quadratic equation to solve it. ^{
}

~Lynne

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