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Find an equation of the circle with center at (-4,5) that is tangent to the y-axis in the form of (x-A)^2+(y-B)^2=C where A,B,C are constant.

A is ?
 
B is ?
 
C is ?
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1 Answer

Since the circle is tangent to the y-axis, r = 4.
(x+4)^2 + (y-5)^2 = 16
Therefore,
A = -4, B = 5, C = 16