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solve 2^(2x+1)-2^x=3

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1 Answer

Hi Leti,
I am from Scottsdale too.
 
Let u = 2x, while u > 0
2u^2 - u - 3 = (2u-3)(u+1) = 0
So, u = 3/2 = 2x
x = log(base 2) (3/2) <=Answer

Comments

log 2 (3/2 ) :

 2 = 3/2

X (lof 2 ) = log 3/2 = log 3 - log 2

 X = ( log 3 - log 2) / log 2 = -0.52