graph the line 3y-4x=12

Question

you have to use a graphing calculator

Answer 1

TO GRAPH LINES YOU HAVE TO FIND THE INTERCEPT WITH AXES MAKING CERO THE VARIABLES:

 

THE FIRST POINT TO GRAPH:     3Y-4X=12 TO FIND X INTERCEP WE MAKE CERO THE VARIABLE  Y  IN THE

 

EQUATION SO WE HAVE 3(0)-X=12...............

 

                                   0-4X=12            4X=12  WE HAVE X=-12/4=3         X=-3

 

        THE FIRS POINT IS (3,0)

 

 

TO FIND THE OTHER POINT WE MAKE CERO THE VARIABLE X:               3Y+2(0)=12        3Y+0=12     3Y=12

 

 3Y=12 WE HAVE Y=12/3=4 SO WE HAVE X=4 THE OTHER POINT WILL BE (4.0)

 

AND WE HAVE THE 2 NECESSARY

 

POINT TO MAKE THE LINE.............GRAPH (-3,O) AND (0,4) ON AXES "X" AND "Y"