√48 =? √x^6y^7=? 9/5/2013 | Harry from Toledo, OH | 1 Answer | 0 Votes Mark favorite Subscribe Comment
48 = 3*4^2 So, √48 =4√3 x^6y^7= (x^3 y^3)^2 y So, √x^6y^7= |x^3| y^3√y --------- Ideas: Factor out squares so that the square root and the square undo each other. 9/5/2013 | Robert J. Comment