
Kirill Z. answered 08/28/13
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OK, look at the sequence of operations. Let x be the number, x≠1.
1) x→x2-1
2) (x2-1)/(x-1)
3) (x2-1)/(x-1)-x
Let us simplify the expression in 3).
(x2-1)/(x-1)-x=(x+1)(x-1)/(x-1)-x=x+1-x=1
We used the fact that x2-1=(x+1)(x-1) to simplify the expression and prove that you will always get 1 no matter what x you take (except x=1, since you can't divide by zero!).
If you subtract the squares of two consecutive numbers, you will end up with their sum as a result. Example: 1112-1102=12321-12100=221; 110+111=221.