how do I work this problem 3+(8-2)*6

Question

trying to figure out how to work order of operations

 

Answer 1

When both writing down and reading the algebraic expressions, the binary operation (including addition+, subtraction-, multiply*, divide/, exponential^) follow a conventional order:

 

0) Parenthesis, including {}, [], ()

1) Exponent, multiply and divide

2) Addition and subtraction

 

The ordering is 0)>1)>2). Then there is no ordering within each group, eg multiply and divide are at the same level of priority except that 0) comes in such as a parenthesis.

 

Thus for your question 3+(8-2)*6.

First compute (8-2)=6;

Then compute (8-2)*6=6*6=36;

Finally compute 3+(8-2)*6=3+36=39.

 

Let's take a look at another example: 3^2+3/(5-2)

First compute (5-2)=3;

Then do 3/(5-3)=3/3=1;

Next compute 3^2=3*3=9;

Finally add 3^2+3/(5-2)=9+1=10.

 

Hope it helps!

Answer 2

Start with the parenthesis first 8-2=6 and then times that by 6 which gives you 36 and then you add three which gives you the answer of thirty nine. A trick to remember this is Peter Michaels divides Susie's Apple:

Parenthesis, Multiplication and Division, Subtraction and Addition. Please note: addition and subtraction are always paired together and multiplication and division are always paired together. I hope this helps you.

Nancy N.

 

Answer 3

Remember PEMDAS, Parenthesis, Exponents, Multiply, Divide, Add, Subtract

 

So 3 + (8-2)*6

Parenthesis first = 3+6*6

Multiply second = 3+36

Add last = 39

 

Dan