
Robert F. answered 08/17/15
Tutor
5
(10)
A Retired Professor to Tutor Math and Physics
v(t)=(t2,5t)
Part 1
x component is a parabola with vertex at (0,0) and opening upward.
y component is a line from (0,0) with a slope of 5.
Part 2
x(t)=5cos(t)
y(t)=-5sin(t)
x2+y2=25[cos2(t)+sin2(t)]=25(1)=25
This is the equation of a circle with radius 5 and center at (0,0)
Part 3
Bearings are measured relative to North with positive angles in the clockwise direction.
cos(60)=1/2
sin(60)=(√3)/2
cos(315)=1/√2
sin(315)=-1/√2
sin(60)=(√3)/2
cos(315)=1/√2
sin(315)=-1/√2
A vector with length 500 and angle 60 relative to north has x,y coordinates of (500sin(60),500cos(60))
A vector with length 40 and angle 315 relative to north has x,y coordinates of (40sin(315),40cos(315))
(500sin(60),500cos(60))=(500(√3)/2,500/2)=(250√3,250)
(40sin(315),40cos(315))=(-40√2,40/√2)
Add the vectors to get a resultant vector with x,y coordinates of
(250√3-40√2,250+40/√2)=(221.716,278.284)
The speed is the magnitude of the resultant vector.
Speed=sqrt(278.2842+221.7162)=355.809
The direction is obtained by observing that the tangent of the angle is 278.284/221.716=1.225
The angle is arctan(1.225)=50.77 degrees (a northeast direction)
A general term that fits the terms that are given is
a0=(-1)0x0/[20(0!)=1
a1=(-1)1x1/[21(1!)=-x/2
a2=(-1)2x2/[22(2!)=x2/8
ai=(-1)ixi/[2i(i!)
Double check the above to make sure that there are no errors.
cos(315)=1/√2
sin(315)=-1/√2