2x(2n - 1) / 6x(2n - 5)
(2/6) * x(2n - 1) / x(2n - 5)
(1/3) * x[(2n - 1) - (2n - 5)]
(1/3) * x4
Yes, you're right.
Nisya R.
asked 08/27/13
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Nisya R.
08/27/13