Ralph L. answered 08/27/13
Tutor
4.5
(2)
Algebra I, II, Visual Basic, Beginning C++ tutor
2x(2n - 1) / 6x(2n - 5)
(2/6) * x(2n - 1) / x(2n - 5)
(1/3) * x[(2n - 1) - (2n - 5)]
(1/3) * x4
Yes, you're right.
Nisya R.
08/27/13