
Shradha S. answered 08/13/15
Tutor
4
(1)
Experienced Maths Teacher with Master's Degree in Mathematics
First draw the figure then it will be more visible..
let the radius of the semi circle be r.
and length of the semicirclr =∏ r
So, its diameter = 2r = breadth of the circle
length of the circle = 3 times radius of the circle
= 3r
and also the length of the side of the equilateral triangle = breadth of the triangle
= 2r
a) perimeter of the farm = length of the boundary = 2r +2r + 3r+ 3r + ∏ r
= 10r + ∏ r
= (10 + ∏) r
b) area of the farm = area of triangle + area of rectangle + area of semicircle
= (√3/4) side2 + length * breadth + ( ∏ r2) / 2
= (√3/4) (2r)2 + (3r)*(2r) +( ∏ r2) / 2
= (√3/4)*4 r2 + 6 r2 + ( ∏ r2) / 2
= √3 r2 + 6 r2 + (∏/2)* r2
= [ √3 + 6+ (∏/2)] * r2
c) area of the farm in terms of the perimeter of the farm = [ √3 + 6+ (∏/2)] * r2
= [ √3 + 6+ (∏/2)] * [perimeter/(10+∏)]2