Inactive Tutor answered 08/13/15
Tutor
New to Wyzant
First draw the figure then it will be more visible..
let the radius of the semi circle be r.
and length of the semicirclr =∏ r
So, its diameter = 2r = breadth of the circle
length of the circle = 3 times radius of the circle
= 3r
and also the length of the side of the equilateral triangle = breadth of the triangle
= 2r
a) perimeter of the farm = length of the boundary = 2r +2r + 3r+ 3r + ∏ r
= 10r + ∏ r
= (10 + ∏) r
b) area of the farm = area of triangle + area of rectangle + area of semicircle
= (√3/4) side2 + length * breadth + ( ∏ r2) / 2
= (√3/4) (2r)2 + (3r)*(2r) +( ∏ r2) / 2
= (√3/4)*4 r2 + 6 r2 + ( ∏ r2) / 2
= √3 r2 + 6 r2 + (∏/2)* r2
= [ √3 + 6+ (∏/2)] * r2
c) area of the farm in terms of the perimeter of the farm = [ √3 + 6+ (∏/2)] * r2
= [ √3 + 6+ (∏/2)] * [perimeter/(10+∏)]2