
Robert F. answered 08/12/15
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A Retired Professor to Tutor Math and Physics
The area under f(x) in the interval [-1,2] is the integral of f(x) over the interval.
The area under g(x) in the interval [-1,2] is the integral of g(x) over the interval.
The difference between the two integrals is the area between the curves over the interval.
Area between the curves
∫[f(x)-g(x)]dx
∫[(-x2+2x+3)-(x+1)]dx over [-1,2]
[-(x3/3)+x2+3x-(x2/2)+x]
[-(x3/3)+x2/2+2x] evaluated with x=2 and then with x=-1 and subtract the latter from the former.
[-(8/3)+2+4]-[(1/3)+1/2-2]
3.5 if I did the arithmetic right.