
Andrew M. answered 08/13/15
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New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Given f(x) = 4log3(x-2) and g(x) = -2log3(x+1) then g(x) = -1/2[f(x+3)]
1. First off we are changing f(x) to f(x+3) when we change (x-2) to (x+1).
This will translate 3 units to the left
2. Then we compress the graph by multiplying by a fraction of 1/2
3. Then we reflect the graph about the x-axis by multiplying by -1
Note: You could say that we compress the graph and reflect it about
the x-axis by multiplying by -1/2
It doesn't really matter which order you take the transformations in.

Andrew M.
The four out front became -2... that means we multiplied the function by -1/2 since 4(-1/2)=-2
The log3(x-2) became log3(x+1)... Thus, within the function we have
(x-2) became (x+3-2)=(x+1)...so we added 3 within the function
Thus g(x)=(-1/2)f(x+3)
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08/13/15
Amber M.
08/13/15