
Ehsan F. answered 08/12/15
Tutor
5
(1)
Experienced Electrical, Computer engineering and Math Tutor
Hi kristin,
Let's Imagine the cylinderical can which has diameter D, and height h, and radius r. Diameter is 4 times its height, So we have D=4*h. Diameter is always twice the radius, So mathematically it would be D=2*r. The surface area of the cylindrical can as the word describes is the area of its surface. So it's the perimeter of its base times its height plus the area of its bottom base(since it is open top cylinder) which is the area of one circle. The area of the circle is pi*[(radius)^2]. and the perimeter of the circle is 2*pi*r. Let me know with this description what should the surface area be eventually.
b)The volume is basically how much it can contain. So for the cylinder, it would be the area of its base which is circle times its height. The area of a circle as said previously is pi*[(radius) ^2]. With this description could you tell me what the volume would be.
Thanks,
Ehsan