Inactive Tutor answered 08/26/13
Tutor
New to Wyzant
Since x < 1, x-4 < 0, and x-3 < 0, |x-4| = -(x-4) = 4-x, and |x-3| = -(x-3) = 3-x
So, |x-4|+|x-3| = 4-x + 3-x = 7-2x <==Answer
Lauren C.
asked 08/26/13Write the expression |x − 4| + |x − 3| without the absolute-value symbols if x is in the given interval. (−infinity, 1)
Inactive Tutor answered 08/26/13
Since x < 1, x-4 < 0, and x-3 < 0, |x-4| = -(x-4) = 4-x, and |x-3| = -(x-3) = 3-x
So, |x-4|+|x-3| = 4-x + 3-x = 7-2x <==Answer
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.