At the equivalence point in a titration involving 1.0 M solutions, which of the following combinations would have the lowest conductivity

Question

A. Nitric acid and barium hydroxide
B. Acetic acid and sodium hydroxide
C. Sulphuric acid and barium hydroxide
D. Hydrochloric acid and sodium hydroxide

 

I dont understand why the answer is c

Answer 1

The lowest conductivity would be the solution with the lowest concentration of ions/strong electrolytes.

A.  2HNO3 + Ba(OH)2 ---> Ba(NO3)2 + 2H2O  and Ba(NO3)2 provides 3 ions

B.  HAc + NaOH ---> NaAc + H2O  and NaAc provides 2 ions

C.  H2SO4 + Ba(OH)2 ---> 2H2O + BaSO4(s)  and there are no ions in solution

D.  HCl + NaOH ---> NaCl + H2O and NaCl provides 2 ions

 

The solution with the lowest concentration of ions is C, because the barium sulfate in insoluble. 

 

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