Mark M. answered 08/01/15
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Retired math prof. Very extensive Precalculus tutoring experience.
By the change of base formula, logab = logb/loga.
So, if a = 3 and b = 7, we have log7/log3 = log37
9(log7/log3) = 9log37 = (32)log37 =32log37 = 3log3(49) = 49 (alogax = x)