Algebra 2 question??

Question

A printer has 8 colors of ink, but can only pick 3 to use on a pamphlet that he is printing. How many different color combination can he choose?

 

A) 24

B) 56

C) 120

D) 336

Answer 1

This is a combination (order does not make a difference, RBG is the same as BGR)

 

₈C₃ = 8! / ((3!)(8 - 3)!)

₈C₃  = 8! / (3!5!)

₈C₃ = (8 · 7 · 6) / (3 · 2 · 1)

₈C₃ = 56