If four timesfour times a number added to 33 is divided by the number plus 88?, the result is sevenseven halves.halves. Find the number.

Question

If four timesfour times a number added to 33 is divided by the number plus 88?, the result is sevenseven halves.halves. Find the number.

Answer 1

The equation could be written another way, given how the problem has been written, but I'll assume this is the equation in question:

 

(4x+33)/(x+88)=(7/2)

 

First, move the (x+88) over to the right by canceling it and distribute the (7/2):

 

((4x+33)/(x+88))*(x+88)=(7/2)*(x+88)

4x+33=(7/2)(x+88)

4x+33=(7/2)x+308

 

Next, move the like terms to the same side and combine:

 

4x+(33-33)-(7/2)x=((7/2)x-(7/2)x)+308-33

4x-(7/2)x=308-33

(8/2)x-(7/2)x=275

(1/2)x=275

 

Now, solve for x:

 

x=275(2)

x=550

 

To check, plug this x back into the original equation and it should work:

 

(4(550)+33)/(550+88)=(7/2)

(2200+33)/(638)=(7/2)

2233/638=7/2

7/2=7/2

 

I hope this helps.