(√3-3√2)2
= (√3-3√2)(√3-3√2)
= √3*√3 - 3*√2√3 - 3√2√3 + 3√2*3√2
= 3 - 6√6 + 18
= 21 - 6√6
Beatriz L.
asked • 06/16/151 assume all variables are positive real numbers
(√3-3√2)2
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