I don't see any reason to do this in decimal form. Like many fraction problems, it's done most easily as a common fraction.
Begin by putting the .21 over the .33. Now you have .21/.33. Get rid of the decimals by multiplying by 100/100. that gives you 21/33. 21 and 33 are both multiples of 3, so reduce by dividing top and bottom by 3. This gives you 7/11, which is the answer. No need for decimals repeating to infinity.
David U.
Is cj a 6th or 7th grader? I see nothing in the original question to indicate this. And while the material may be considered 6th or 7th grade level (or even younger), I've encountered more than a few college students who find such problems challenging. So I wouldn't want to make any assumptions of that kind.
Furthermore, in my experience students often misunderstand exactly what is required and what isn't. In this case, for example, even if the answer is required to be in decimal format, I think it's far easier to do as I've suggested, and then convert the 7/11 into decimal format by dividing 11 into 7.0000...
Of course there are many different ways to do almost any problem, and individual preferences as to which way is best can vary.
08/01/13
Jacqueline S.
09/27/13
Nataliya D.
Well, Mr. David U, I don't see any reason to do all those procedures (above and under of this comment) either, but if you are 6th or 7th grade student, all those steps are a requirement.
08/01/13