Sara N.

asked • 06/08/15

If 5 g of sodium bicarbonate is combined with water to make a 100 ml solution, how do I find out how many grams in the final solution?

In chem lab we did a quality control test to determine if the label for sodium bicarbonate (baking soda) is accurate. The label says there is 1,258.56 mg of sodium in a 5 g serving.

We made a solution using 5 g of sodium bicarbonate and 100ml of DI water. We titrated 20ml of the solution with .1M HCl standardized solution, and the average amount of HCl used after 3 titrations was 22.23 ml to reach end point.
 Given this information, how do I compare our results to determine how close they are to the advertised value?
I am having a hard time figuring out grams, as I am not 100% sure what our concentration is. I am not sure even if the "sodium" listed would be NaCl, the product, or the sodium bicarbonate itself, NaHCO3. I am assuming this will have an effect on the results.

I have done M1V1 = M2V2 and get .1115 moles of sodium bicarbonate used but not sure if it is accurate, as that is 9.335g, which is a lot higher than the 1.26 g of sodium per 5 g that is listed on the label.
Can someone please help me with steps to compare the results to the advertised values on the label?

PLEASE HELP if you can!! :)

1 Expert Answer


Steve C. answered • 06/08/15

5.0 (641)

Steve C. Math & Chemistry Tutoring

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