Word Problem --Equation

Question

A piggy bank contains 91 coins whic are nickles, dimes and quaters. There are twice as many quaters as dimes, and half as many as dimes. Determine how much is in the piggy bank.

Answer 1

Assuming you mean nickels in the second sentence: "... and half as many nickels as dimes."

 

Let,

no. of dimes = x

 

no. of quarters = 2x ( There are twice as many quarters as dimes)

 

no. of nickels = x/2 ( half as many nickels as dimes)

 

Then,

total no. of coins = x + 2x + x/2 = 91

(2x + 4x + x)/2 = 91

7x/2 = 91

x = 26

 

so,

we have 26 dimes = 26*$0.10 = $2.60

no. of quarters = 2*26 = 52 = 52*$0.25 = $13.00

no. of nickles = (1/2)*26 = 13 = 13*$0.05 = $0.65

Total money in the piggy bank = 2.60 + 13.00 + 0.65 = $16.25