Can you walk me through how to evaluate the 1st one and simplify the 2nd please?

Question

m(2 + n – m) + 3(3n + m2 – 1) =

33/45 divided by 63/25

Answer 1

I think you meant simplify the 1st and evaluate the 2nd. If that is the case then for the 1st problem you begin by distributing the m and the 3, this should give you:

m(2 + n - m) + 3(3n + m² - 1) = 2m + nm - m² + 9n + 3m² - 3.

Next combine like terms, this will give you:

2m + nm - m² + 9n + 3m² - 3 = 2m² + 2m + mn + 9n - 3. Since there are no more like terms to combine you are done.

to divide 33/45 by 63/25 we instead multiply 33/45 by the reciprocal of 63/25, which is 25/63. We do this because multiplying fractions is much simpler than dividing them.

So we have (33/45)/(63/25) = (33/45)*(25/63).

To multiply fractions we simply multiply the numerator with the numerator and denominator with the denominator. Before you do that it is always a good idea to see if anything can cancel and in this problem you should notice that the 33 and 63 can cancel and give you 11 and 21 and the 25 and 45 cancel to give 5 and 9.

After the canceling the problem becomes: (11/9)*(5/21) = 55/189