Inactive Tutor answered 05/24/15
Tutor
New to Wyzant
Josh, none of the answers are correct. You can actually check it by substituting your answers back into the equation.
For example, let's check if x=2/3 is one of the solutions of |3x-5| = 7
|3(2/3) - 5| = 7
|2 - 5| = 7
|-3| = 7
3 = 7
Which is not correct. So, x=2/3 is not one of the solutions of |3x-5| = 7
You can also check your answers in 2 and 3 by plugging them back into the equations.
So what's the correct answer? Let's do problem 1
|3x-5| = 7
3x - 5 = 7 or 3x - 5 = -7
3x = 7+5 or 3x = -7+5
x = 12/3 or x = -2/3
x=4 or x= -2/3
So there are actually two solutions: x=4 and x=-2/3
Second problem is similar to the first problem, so I am leaving it for you to work it out.
Let's look at problem 3
3|x2-3x-1| -3 = 3
|x2-3x-1| -1 = 1 (divided each side with 3)
|x2-3x-1| = 2 (added 1 on each side)
x2-3x-1 = 2 or x2-3x-1 = -2
x2-3x-3 = 0 or x2-3x+1 = 0
x = (3 ± √21)/2 or x = (3 ± √5)/2
So, you have 4 solutions: x = (3 ± √21)/2 and x = (3 ± √5)/2
Inactive Tutor
Note: the ± each give two solutions and there are two sets of quadratic equation results.
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05/26/15
Josh F.
05/26/15