Algebra problem

Question

3yx^2/3 times yx^-7/4

Answer 1

3yx^2/3 times yx^-7/4

 

(3yx^2/3)(yx^-7/4) = 3(y)(y)(x^2/3)(x^-7/4) = 3y²(x^2/3-7/4) = 3y²x^-13/12

 

Answer 2

3y²x^(-13/12)

Can keep the 3.

y times y is y²

for the x exponents, you have to add them which would be x^(-13/12)