The length of a rectangle is 11 ft more than double the width, and the area of the rectangle is 63 ft2 . Find the dimensions of the rectangle.

Question

Length

Width

Answer 1

Let width = x

Let length = 2x + 11

Area = 63 ft²

 

 

length × width = Area

 

x(2x + 11) = 63

 

2x² + 11x = 63

 

 

Subtract 63 on both sides of equation.

 

2x² + 11x - 63 = 0

 

 

Factor the left side of equation.

 

(2x - 7)(x + 9) = 0

 

x = 7/2        and       x = -9

 

 

Since the dimensions cannot be negative, we accept the positive value of x:   x=7/2.  Substitute this value of x into the dimensions

 

width = 3.5 ft

length = 2(3.5) + 11 = 7 + 11 = 18 ft