Stephanie M. answered 05/02/15
Tutor
5.0
(965)
Private Tutor - English, Mathematics, and Study Skills
I think this problem is asking you to find a section of the circle's area. You can think of the entire area of a circle as the area between 0° and 360°, since 360° is a full rotation. This problem wants you to find the area between 125° and 212°. That's a total of 212 - 125 = 87°, which is 87/360 = 29/120 of the circle's total area. We'll use this fact later.
First, let's find the circle's area.
A = πr2
A = π(3)2
A = 9π
The circle's total area is 9π m2. But we're only looking for 29/120 of that. So, the area of the sector of the circle we're interested in is:
As = (9π)(29/120)
As = (261π)/120
As = (87π)/40
As ≈ 6.83
Therefore, the area of the circle between the given degrees is approximately 6.83 m2.