Let width W of the rectangle = x
Therefore, by problem statement, length L of the rectangle = x + 5 (5 ft. longer than width)
Area of rectangle = 84 sq ft. (given)
By formula, Area of rectangle = L times W
Therefore
84 = (x + 5) (x)
Or, 84 = x^2 + 5x
subtracting 84 from both sides you get x^2 + 5x -84 = 0
x^2 + 5x -84 = 0
x^2 + 12x - 7x - 84 = 0 factorization
x(x + 12) - 7(x + 12) taking commons out
x - 7 = 0 OR x + 12 = 0
x = 7 OR x = -12
Since the width of the rectangle cannot be negative we can discard the negative value for x, therefore x = 7
x (width of the rectangle) = 7ft
By problem statement, length is x + 5 therefore, length = 12ft
Verify: Given area of rectangle is 84sq ft. which is L times W (12 times 7 = 84)