
Tamara J. answered 05/24/13
Math Tutoring - Algebra and Calculus (all levels)
sec2(x) - sec2(x)csc2(x)
Since sec2(x) is a common factor among the two terms in the expression, factoring it out will yield the following:
sec2(x)(1 - csc2(x))
Recall the following pythagorean trig identity: 1 + cot2(x) = csc2(x)
subtracting csc2(x) from both sides of the equation we get the following:
1 + cot2(x) - csc2(x) = 0
subtracting cot2(x) from both sides of the equation we get the following:
1 - csc2(x) = -cot2(x)
We can substitute this back into the original expression after we factored out sec2(x):
sec2(x)(1 - csc2(x))
sec2(x)(-cot2(x))
-(sec2(x)cot2(x))
Recall the following identities:
Reciprocal identity: sec(x) = 1/cos(x) ==> sec2(x) = 1/cos2(x)
Quotient identity: cot(x) = cos(x)/sin(x) ==> cot2(x) = cos2(x)/sin2(x)
Substituting these identities into the simplified expression, we arrive at the following:
-(sec2(x))(cot2(x))
-(1/cos2(x))(cos2(x)/sin2(x))
-(1/sin2(x))
Another reciprocal identity involving sin is the following:
1/sin(x) = csc(x) ==> 1/sin2(x) = csc2(x)
Therefore,
-(1/sin2(x)) = -(csc2(x))
Thus,
sec2(x) - sec2(x)csc2(x) = -csc2(x)