(t+7)^2/t+2 * (t+2)^2/t+7=?

Since (t + 7) occurs in both a numerator and a denominator, we can eliminate one of them from the first numerator and the one from the second denominator

Since (t +2) occurs in both a numerator and a denominator, we can eliminate one of them from the second numerator and the one from the first denominator

After canceling terms, we have:

(t + 7)(t + 2)

t^{2} + 9t + 14