2.4% increase 1400 cats, how many in 8 years

Question

the number of cats increases exponentially at 2.4% per year. How many cats in 8 years

Answer 1

Set up an exponential growth equation with final population P(t), initial population a = 1400, rate of increase r = 1.024, and amount of time that has passed t:

 

P(t) = ar^t

P(t) = 1400(1.024)^t

 

Plug in t = 8 and solve for P(8) to find the new population of cats after 8 years:

 

P(8) = 1400(1.024)⁸

P(8) = 1400(1.209)

P(8) = 1692.496

 

There are approximately 1692 cats after 8 years.