What is the probability of selecting and eating 2 Snickers bars?

Question

You buy a bag of candy. There are 7 Kit-Kat Bars, 9 Snickers, 6 bags of M&M’s, 4 Butterfingers, and 1 Twix. What is the probability of selecting and eating 2 Snickers bars?

Round answer (in decimal form) to the nearest thousandth

Answer 1

Adding up all the candies, there are a total of 27 candies in the bag. 9 of those are Snickers. So your chance of picking that first Snickers is 9/27 = 1/3.

 

What about the second one? You're now left with 26 candies, 8 of them being Snickers. Your chance of picking a Snickers now is 8/26 = 4/13.

 

So, your chance of picking 2 Snickers bars is:

 

(1/3) * (4/13) ≈ 0.103