(3 t-2)(7 t-4) equals At^2+Bt+C

Question

(3 t-2)(7 t-4) equals At^2+Bt+C
where A equals:

where B equals:

where C equals:

Answer 1

(3t-2)(7t-4)

 

21t^2-12t-14t+8

 

21t^2-26t+8

 

A=21

B=-26

C=8