Inactive Tutor answered 05/08/13
Hi Jamal,
To factor this completely, you start by determining the first, most apparent factor, which you get by setting the expression equal to zero and solving for z.
You get z^3 = -125 ------>> z = -5
Therefore, one of your factors is (z+5).
To get the other two, you need to divide this factor into the expression, so you set up the synthetic division like this:
-5 1 0 0 125
-5 25 -125
1 -5 -125 0
(The -5 is what you're dividing by. The other numbers are the coefficients of the 3rd order polynomial, with zeros in place for the missing x^2 and x terms. Simply bring down the first coefficient unchanged, then multiply by the dividing factor and add to the next coefficient.)
These numbers become the coefficients of a polynomial one order less than the original, in this a quadratic:
x^2 -5x +125
This cannot be factored, so we use quadratic formula:
(5 +- sqrt(25 - 4*125))/2
= (5+- sqrt(-475))/2 = (5 +-sqrt(-1)*sqrt(25)*sqrt(19))/2
= 2.5 +- 2.5i*sqrt(19)
So the fully factored polynomial is
(2.5 + 2.5i*sqrt(19)) (2.5 - 2.5i*sqrt(19)) (x + 5)
Jamal M.
I need this re did so I can read the answer which is what ?
05/09/13
Inactive Tutor
Hey Jamal,
There was actually a mistake here (though I posted a comment about it already, but don't see it)
The reduced quadratic equation from they synthetic division is:
x^2 - 5x + 25
Since this is prime, the solution is (x+5)(x^2 -5x + 25)
05/10/13
Inactive Tutor
05/08/13