
Tamara J. answered 05/08/13
Math Tutoring - Algebra and Calculus (all levels)
3x2 + 17x - 6
(a)
1.) determine the greatest common factor (gcf), if any:
==> since there is no common factor that divides into each term of the polynomial equally, there is no gcf
2.) set up a product of two binomials:
==> ( )( )
3.) find the first terms of the binomials:
==> factors of 3x2 : 3x and x
==> (3x )(x )
4.) find the second terms of the binomials:
==> factors of -6 : -1 and 6 , 1 and -6 , -2 and 3 , or 2 and -3
5.) use trial and error to determine which pair of factors make up the second two terms of the binomials:
==> (3x - 1)(x + 6) = 3x2 + 18x - x - 6 = 3x2 + 17x - 6
==> (3x + 1)(x - 6) = 3x2 - 18x + x - 6 = 3x2 - 17x - 6
==> (3x - 2)(x + 3) = 3x2 + 9x - 2x - 6 = 3x2 + 7x - 6
==> (3x + 2)(x - 3) = 3x2 - 9x + 2x - 6 = 3x2 - 7x - 6
Notice that the only pair of factors of -6 that yield the correct trinomial is the first, -1 and 6. Thus, the factored form of the original trinomial is:
3x2 + 17x - 6 = (3x - 1)(x + 6)
(b) Since this polynomial is factorable it is not a prime polynomial.