Mark M. answered 04/18/15
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Retired college math professor. Extensive tutoring experience.
h(x) = 5√(x-1) + 3
Let y = h(x) : y = 5√(x-1) + 3
Switch x and y : x = 5√(y-1) + 3
Solve for y: x-3 = 5√(y-1)
(x-3)5 = y-1
y = (x-3)5 + 1
f-1(x) = (x-3)5 + 1