i need help asap

Here is a method that I always teach my students.

Given **ax ^{2} + bx + c = 0**, find two integers with

**b**as the sum and

**ac**as the product.

With 4x^{2} - 5x + 1 = 0, for example, you want two integers with a sum of -5 and a product of 4*1 = 4.

The only pairs of integers (order doesn't matter) with a product 4 are

(1,4), (2,2), (-1,-4), (-2,-2)

The only pair in this list with a sum of -5 is (-1,-4)

You can now factor by grouping:

4x^{2} - 5x + 1 = 4x^{2} - 4x - x + 1 = 4x(x - 1) - 1(x - 1) = (4x - 1)(x - 1).

(4x - 1)(x - 1) = 0

4x - 1 = 0 or x - 1 = 0

x = 1/4 or x = 1