Edward C. answered 04/16/15
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Caltech Grad for math tutoring: Algebra through Calculus
The basic equation is Distance = Rate times Time
Let R = rowing rate in still water
Let C = rate of the current
The upstream rate is R - C and the downstream rate is R + C
The Distance D = 12 mi is the same in both cases
So the 2 equations are
12 = (R - C)*1.75 = 1.75*R - 1.75*C upstream
12 = (R + C)*1 = R + C downstream
Multiply the 2nd equation by 1.75 and then add the 2 equations together
12 = 1.75*R - 1.75*C
21 = 1.75*R + 1.75*C
33 = 3.5*R + 0*C
R = 33/3.5 = 66/7
Plug this value in for R in the downstream equation and solve for C
12 = 66/7 + C
84 = 66 + 7*C
7*C = 18
C = 18/7 mi/hour is the rate of the current
Check: Upstream rate = 66/7 - 18/7 = 48/7 mi/h so to go
12 miles would require 12 / (48/7) = 12*(7/48) = 7/4 = 1 and 3/4 hours
Downstream rate is 66/7 + 18/7 = 84/7 = 12 mi/h so to go 12 mi would require 1 hour