x + 3(2-x) ≥ 7
Distribute (multiply) the 3 across the terms in the parentheses:
x + 6 - 3x ≥ 7
Subtract 6 from both sides and combine like terms:
-2x ≥ 1
Divide both sides by -2. When we multiply or divide an inequality by a negative number, we flip the inequality; in this case, from ≥ to ≤:
x ≤ -1/2
In interval notation:
(-∞,-1/2]