
Allison L. answered 04/30/13
Multidisciplinary Educator with a Background in Special Needs
2a3 + 16a2 + 30a CAN be factored
First, find the greatest common factor (GCF) in each of the terms:
The GCF is 2a; therefore:
= 2a (a2 + 8a + 15)
Now, you are left with a quadratic equation to factor in a (a+n)(a+r) fashion:
It helps to first find the factors of 15: 1, 3, 5, 15
3+5=8; so, 3 and 5 will be the numbers for n and r
= 2a (a + 3) (a + 5)