With whatever method is easiest...substitution or elimination?

You can also cancel -y and +y just by adding this two equations. so when you add it just left with:

4x=4

x=1

then plug back 1 to one of the equation.

1-y=6

1-6=y

y=-5

With whatever method is easiest...substitution or elimination?

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You can also cancel -y and +y just by adding this two equations. so when you add it just left with:

4x=4

x=1

then plug back 1 to one of the equation.

1-y=6

1-6=y

y=-5

I would solve for x with the first equation, then use that to solve for y in the second, then check by inputting values.

3x+y=-2

x-y=6

x=6+y

then...

3(6+y)+y=-2

18+3y+y=-2

18+4y=-2

4y=-20

y=-5

So..

3x+-5=-2

3x=3

x=1

3(1) + -5 = -2 ... yes! :)

In this scenario, the goal of finding the values of both x and y the fastest is to find which variable will be easiest to solve and determine its values, which in this case must be x because you can use elimination or substitution to derive at x.

Elimination Process:

3x+y=2 and x-y=6 (adding them together)

4x=8 --> x=2

2-y=6 --> (through common sense) y=-4 since 2-(-4)=2+4=6

Test the solution witht he other equation:

3(2)+(-4)=6-4=2

Substitution Method: (as written above margery b.)

The key here Angelica is to use your instinct and determine what variable is best to be eliminated first so that you are left with only one variable to solve.

If you need any further help on your math, please check my profile or shoot me another email for tons of mathematical magics.

-Andy Lai "If adversary smiles, military people smiles back"

I prefer Elimination myself although the beauty of math allows more than one method with the same result. Please note that Andy's answer is only different because he had the 1st equation wrong.

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