Like graphing quadratic equations

y = x^{2} - 6x + 4

Use an equation that will help us find the x of our vertex point (x,y)

equation for x of your vertex = -b/2a

this equation

a = 1, b = -6, c = 4

vertex x = -(-6)/2(1) = 6/2 = 3

Take the x you just found and plug it back into original equation to find the y of your vertex

y = (3)^{2} - 6(3) + 4 = 9 - 18 + 4 = -5

Vertex is: (3,-5)

Now you can chose one or two points on either side of your vertex x and plug in to find a couple more points. Because vertex x = 3, lets use 2 and 4

y = (2)^{2} - 6(2) + 4 = 4 - 12 + 4 = -4 Point = (2,-4)

y = (4)^{2} - 6(4) + 4 = 16 - 24 + 4 = -4 Point = (2,-4)

If you need a couple more points then choose x to be 1 and 5.

## Comments

Can you please give me a specific problem?

y=x^2-6x+4