Dianne Z. answered 04/28/13
Patient and Effective ESL/ESOL Tutor with 20 years experience
Greetings Jamal,
"First, last, inner, outer" is the way I remember solving this type of equation.
(2v + 5) (2v -5) = ?
- To begin, there is no sign between the parentheses, so you are going to use multiplication to arrive at your solution.
- First = the first figure in each parenthesis. So that's 2v x 2v = 4v "squared". (Sorry, my computer doesn't type exponents.)
- Last = the last figure in each parenthesis. So that's (+5) x (-5) = -25.
- Inner = the 2 figures that are in the most internal place in the pair of parentheses. So that's (+5) in the first parenthesis times (2v) in the second parenthesis. Notice that 2v is in both parentheses.
Now you've got 2v + 5. - Outer = the 2 figures in the most external position in the pair of parentheses. That is 2v in the first parenthesis and -5 in the second parenthesis. So now you've got 2v - 5.
Alright? - Let's put all of the figures together now:
(2v + 5) times (2v - 5) =
first: 2v x 2v = 4v squared
last: (+5) (-5 )= -25
inner: +5 x 2v = 10v
outer: -5 x 2v = -10v
It will look like this: (4v)squared - 10v + 10v -25 =
(4v)squared - 25 (Remember that -10v +10v = 0)
I hope this helps.
Dianne from Boston MA