Inactive Tutor answered 04/26/13
Hello.
(1*1)-(6a*1)-(7a*1)+(6a*7a)
1-6a-7a+42a^2
42a^2 - 13a + 1
Jamal M.
asked 04/26/13(1-6a)(1-7a)=?
Inactive Tutor answered 04/26/13
Hello.
(1*1)-(6a*1)-(7a*1)+(6a*7a)
1-6a-7a+42a^2
42a^2 - 13a + 1
Inactive Tutor answered 04/26/13
Traditionally, people will tell you to use the "FOIL" method (First, Outside, Inside, Last). It works in this situation, but it doesn't if you don't have two binomials.
I like to think of it as a dance: each term on the left dances with each term on the right. Then you combine the "like terms" and there you have it.
(1)(1) + (1)(-7a) + (-6a)(1) + (-6a)(-7a) yields
1 -7a -6a + 42a^2 = 42a^2 -13a +1 (in descending order)
This works with other types of polynomials. For example, (2x +1)(x^2 -4x +7):
(multiplied) 2x^3 -8X^2 +14x + 1x^2 -4x +7 (combined) 2x^3 -7x^2 +10x +7
It's just the distributive property, which is not limited to examples such as 3(x +7). In this case you just have the 3 dancing with the x and the 7. No difference!
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