Sun K.

asked • 04/25/13

What is the y-component of r(pi/2)?

If r'(t)=<sin(t), -cos(t), 2t> and r(0)=<1, 1, 2>. What is the y-component of r(pi/2)?

r(t)=<-cos(t), -sin(t), t^2>

r(pi/2)=-1

So -1 is the answer?

Sun K.

Thanks to Robert.

Report

04/25/13

2 Answers By Expert Tutors

By:

Giorgi S. answered • 04/25/13

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4.8 (46)

George PhD: Math and Physics - any concept can be understood

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