I need to know the answer to this question. The length of a rectangle is twice its width. The perimeter is 60ft. What is the area. Please explain in complete sentences the steps necessary to find the area.

Set the following: Length = L Width = W

The length is twice the width: L = 2*W or: W = L/2

Perimeter: P = 60ft = 2*L + 2*W

Substituting L for W in the perimeter equation gives:

P = 60ft = 2*L + 2*(L/2) = 2*L + L = 3L

L = 60ft/3 = 20ft W=L/2=20ft/2=10ft

Verify result: Perimeter= P = 60ft = 2L + 2W = 2*20ft +2*10ft = 40ft+20ft = 60ft

The area of the rectangular is: Area = A = Length*Width = L*W = 20ft*10ft = 200 (ft)^2