Colby W. answered 04/10/13
Tutor
New to Wyzant
Math and science tutor
You can multiply the 3 and 2 in the second factor.
8a - 3b2c - 2 = 8a - 6bc - 2
And if you want, you can factor a 2 from all of the terms : 8a - 6bc - 2 = 2*(4a - 3bc - 1)