
Dayv O. answered 06/07/25
Caring Super Enthusiastic Knowledgeable Calculus Tutor
someone hopefully has explained to you
the definition of derivative of f(x) at x0 is f'(x0)= lim h->0 of [f(x0+h)-f(x0)]/h
f(x)=x3 and x0=4 fit the problem
since f'(x)=3x2 for f(x)=x3
the limit for h->0 [(4+h)3-64]/h
is 3(42)=48
Dayv O.
for +.5,,,,,,, (91.125-64)/.5=54.25. for-.05,,,,,(42.875-64)/-.5=42.25,,,,,limit h->0 is 48.06/07/25