
All G.
asked 06/05/25Guess the value of the limit (if it exists)
Guess the value of the limit (if it exists) by evaluating the function at the given numbers:
x = 5.1, 5.05, 5.01, 5.001, 5.0001,
... 4.9, 4.95, 4.99, 4.999, 4.9999
Guess the value of the limit (correct to six decimal places). (If an answer does not exist, enter DNE.)
2 Answers By Expert Tutors
No guessing ! Hah !
Recall the Definition of a Limit of f(x) at x₀ is not just about the value a function “tends” to at x₀, regardless of the actual value the function is defined to have at x₀, but f(x) must be defined on an "open interval" containing x₀, even if undefined at x₀ itself.
We cannot speak of a Limit without speaking of a suitable Open Interval for f(x) around x₀, in both directions around x₀.
On an open interval like (-4, 6), the limit does exists as x/(x + 5) = 5/10 = 1/2… (I will dispense with the decimals)
On the interval (-10, 10), the same limit does not exist, as a matter of definition, due to f(-5) being undefined on the specified open interval (DNE)
On (5, 10), the following "one-sided limit” (“right-handed limit") does exist: lim x->5⁺ (x² - 5x) / (x² - 25), but the limit does not. Why not ? Definitions… ! Which part ? (see above)
On (-5, 5), the following "one-sided limit” (“left-handed limit") does exist: lim x->5⁻ (x² - 5x) / (x² - 25), but the limit does not. Again, why not ? [Hint: It is not about the -5… why not ? And why does the limit not exist again ?]

Mark M. answered 06/06/25
Mathematics Teacher - NCLB Highly Qualified
Does the limit exist? Why or why not?
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Doug C.
See if this graph gives you some ideas: desmos.com/calculator/i7eoozsoqe06/05/25